White to move and win.
Source: Kling, 1852
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Chaotic tactic
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White to move and win.
Source: Kling, 1852
I see Bd5+!, if qxd5 then rxd2+, Qxd2 Nxf3+!
Doesn’t work.
I see 1.axb8=Q+, Qxb8 2.Bd6+ Qxd6 3.Rxd2+ Qxd2 4.Nxf3+ and then 5.Nxd2, with a B+N mate.
1. axb8=Q Qxb8
2. Bd6 Qxd6
3. Rxd2 Qxd2
4. Nxf3
Anon @4:19 got it almost right. Correct would be:
1. axb8Q+ Qxb8
2. Bd6+ Qxd6
3. Rxd2+ Qxd2
4. Nxf3+ K~
5. Nxd2
And now white wins.
how about
1.axb8Q+ Qxb8
2.Bd6+ Qxd6
3.Rxd2+ Qxd2
4.Nxf3+
queen the pawn, check with the bishop, take the bishop with check, knight forks the queen, white wins.
1.axb8Q+ Qxb8
2.Bd6+ Qxd6
3.Rxd2+ Qxd2
4.Nxf3+ K~
5.Nxd2 +-
1. axb8(Q)+ forking the queen and king
1. … Qxb8
2. Bd6+ forking the queen and king
2. … Qxd6
3. Rxd2+ forking the queen and king
3. … Qxd2
4. Nxf3+ forking the queen and king
4. … K moves
5. Nxd2 and all White has to know is how to mate with a bishop and knight.
Anonymous at 4:19 got the main idea, that the black queen should be driven to the d2 square and then the white knight could capture it with double check on the f3 square. However, the move order does make a difference. Here is my solution.
1. axb8=Q+, Qxb8
2. Bd6+, Qxd6
3. Rxd2+, Qxd2
4. Nxf6+, …
Now black king moves and then
4.Nxd2,
arriving at a winning endgame of K+B+N vs K.
A)
1.Rd2+ Kg3 2.axb8(Q)+ Qxb8 3. Bd6+ wins the Black Queen.
B)
1. Rxd2+ Kh1 2.axb8(Q) Qxb8 3.Nxf3 Qg3+ 4.Kh6 Qh3+ 5.Kg6 Qg3+ 6.Ng5 Qd3+ 7.Kh5! and White has too many pieces.
Kamalakanta
It’s funny, though rather easy:
1.ab8:Q+ Qb8:
2.Bd6+ Qd6:
3.Rd2:+ Qd2:
4.Nf3:+ K..
5.Nd2: – and the rest is a matter of knowing how to mate with Bishop and Knight 🙂
1.axb8+=Q Qxb8 2.Bd6+ Qxd6 3.Rxd2+ Qxd2 4.Nxf3+ 1-0
Amazing puzzle.
1. axb8=Q+ Qxb8
2. Bd6+ Qxd6
3. Rxd2+ Qxd2
4. Nxf3+ Kg2
5. Nxd2
Knight and bishop is a won endgame.
How about b8(Q)+ Qxb8 Bd6+ Qxd6 Rxd2+ and mate with N and B.
It’s all about checking: 1.abQ+ Qb8
2. Bd6+ Qd6 3. Rd2+ Qd2 4. Nf3+ K~ 5. Nd2 +- Luckily, mating with bishop and knight isn’t as hard as most people think
“B)
1. Rxd2+ Kh1 2.axb8(Q) Qxb8 3.Nxf3 Qg3+ 4.Kh6 Qh3+ 5.Kg6 Qg3+ 6.Ng5 Qd3+ 7.Kh5! and White has too many pieces.”
My apologies. I was doing it without the board. In the above variation, 6…Qd3+ loses to 7.Rxd3.
Kamalakanta