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      Home  >  Chess Improvement • Chess Puzzles  >  Checkmate in 5

      Checkmate in 5

      Chess tactic, Puzzle Solving



      Akobian vs. Ortiz, 2003

      White to move and checkmate in 5.

      1n4k1/ppq3b1/4p2R/2p2r2/2PrNpQ1/2N3P1/PP6/2K4R w – – 0 1

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      5 Comments

      1. pht Reply
        March 28, 2014 at 9:42 am

        Initially I notice that my knight’s control of both f6 and d6 looks important, it should give me a mate if I also gain control of both 8th and 7th rank!

        So I first eliminate:
        Nf6+?
        Loosing control of f6 and d6.

        Next I reject this plan:
        Rh8+(?) Kf7
        R1h7
        This is answered with Qe6!
        Bg7 is well defended and white attack is heavily slowed down.

        But I will stick to my initial plan of gaining control of both 8th and 7th rank. An important issue here is that Rf5 must not get opportunity to be interposed!

        I should really have liked to have my queen on g6, so why not:

        1. Qg6!

        Not a check, but the threat Rh8# at first glance seems to give black no alternative to:

        1. … Kf8(?)

        Unpinning g7.
        Here I am well into my initial plan! I can even afford a sack:

        2. Rh8+! Bxh8

        Enforced. Ke7? Qe8#.

        3. Rxh8+ Ke7
        4. Qe8#

        Quite simple, if it wasn’t for the problem that 4 moves is one too quick so I must have missed something.

        Of course it must be:

        1. Qg6 Rd1+(!)

        Here it is pretty obvious that black looses, but can I make it a mate in 5?
        To avoid more delaying sacks, I must surely answer with:

        2. Rd1

        But without double rook in h file, my initial plan doesn’t work. Black seems to have several options to keep it going for a while.
        I have to ponder more on this….

      2. pht Reply
        March 28, 2014 at 10:01 am

        Well, of course it is:

        1. Qg6! Rd1+ (only delay)
        2. Nxd1! Kf8 (now only against Rh8#)
        3. Rh8+! Bxh8
        4. Rxh8+ Ke7
        5. Qe8#

        I think it’s now proved that mate in 5 is slightly more difficult than mate in 10…

      3. pht Reply
        March 28, 2014 at 11:30 am

        Also worth to mention is that the somewhat brilliant looking:

        1. Rh8+(?) Kf7
        2. Qxg7(?) Kxg7
        3. R1h7+ Kg6
        4. Rxc7 f3(!)

        Is probably winning for white with
        5. Nf2
        But very far from mate in 5….

      4. Prof.S.G.Bhat Reply
        March 28, 2014 at 2:45 pm

        This I can attempt,however mate in 10 is a project.
        1.Qg6 Rd1+(delay tactic)
        2.Nxd1 Kf8

        2…. Rh5 3.Nf6+ Kf8 4.Qe8#
        3.Rh8+ Bxh8

        3….. Ke7 4.Qe8#
        4.Rxh8+ Ke7
        5.Qe8#

      5. Anonymous Reply
        March 28, 2014 at 3:08 pm

        I can’t find it.

      Leave a Reply to Prof.S.G.Bhat Cancel reply

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