White to move. How should white proceed?
1r1r3k/7p/5P2/4Rp2/2nB1p2/p6n/1p5P/4R2K w – – 0 1
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White to move. How should white proceed?
1r1r3k/7p/5P2/4Rp2/2nB1p2/p6n/1p5P/4R2K w – – 0 1
Rd5 RxR f7# Easy peasy.
Mate in 5!
1 Re8
2 Re8
3 f7
4 Be5
5 f8mate
1.Re8+ Rxe8
2.Rxe8+ Rxe8
3.f7+ Ne5 (if 3… Re5 4f8=Q#)
4.Bxe5+ Rxe5
5.f8=Q#
Anonymous 8:34PM,
Black doesn’t need to take the rook on d5, so it’s not a forced mate line. I’d suggest: 1.Re8+ Rxe8 2.Rxe8+ Rxe8 3.f7+, and now if 3…Re5, 4.f8=Q#; if 3…Ne5, then 4.Bxe5+ Rxe5 5.f8=Q#.
1. Re8+ Rxe8
2. Rxe8+ Rxe8
3. f7+ (A) Ne5
4. Bxe5+ Rxe5
5. f8=Q#
OR (B)
3… Re5
4. f8=Q#
1. Re8+ Re8
2. f7#
Re8+ Rxe8
Rxe8+ Rxe8
f7+ Ne5
Bxe5+ Rxe5
f8=Q++
Very Wonderfull
This one is cool.
1. Re8+ Rxe8
2. Rxe8+ Rxe8
3. f7+ Ne5
4. Bxe5+ Rxe5
5. f8=Q#
Rd5 RxR f7# Easy peasy Doesn’t work because RxR isn’t forced.
1)Re8+ Rxe8 2)Rxe8+ Rxe8 3)f7+ (if …Ne5 then 4)Bxe5+ Rxe5 5)f8=Q# or if 3)…Re5 then 4)f8=Q# Forced all the way.
1.Re8+ Rxe8
2.Rxe8+ Rxe8
3.f7+ Ne5
4.Bxe5+ Rxe5
5.f8Q#
Rd5 RxR f7# Easy peasy doesn’t work because RxR isn’t forced.
1)Re8+ Rxe8 2)Rxe8+ Rxe8 3)f7+ (if Ne5 then 4)Bxe5+ Rxe5 5)f8=Q#) if 3)f7+ Re5 then f8=Q# Forced all the way.
1)Re8+ Rxe8 2)Rxe8+ Rxe8 3)f7+ Ne5 4)Bxe5+ Rxe5 5)f8=Q mate
if 3)…Re5 4)f8=Q mate
1. Re8+ Rxe8
2. Rxe8+ Rxe8
3. f7+ Ne5
4. Bxe5+ Rxe5
5. f8=Q++
Easy peasy should take a look at the pawn on b2.
Busy cheese!
1.Re8+ Rxe8 2.Rxe8+ Rxe8 3.f7+ Ne5 4.Bxe5+ Rxe5 5.f8=Q#
1Re8 rxr 2Rxr rxr 3 f7+
either knight or rook interpose
cannot save the mate Qf8
1. Re8+ Rxe8
2. Rxe8+ Rxe8
3. f7+ Ne5
4. Bxe5 Rxe5
5. f8=Q
If 3 .. Re5 then 4. f8=Q
–S
Re8 ch ; Rxe8
Rxe8 ch ; Rxe8
f7 ch ; Ne5
Bxe5 ch ; Rxe5
f8(Q) mate
Not that hard at all!!
Re8+ RxR Re8+ RxR f7+
1. Re8+ Rxe8 (only)
2. Rxe8+ Rxe8 (only)
3. f7+ Ne5 (Re5? f8=Q#)
4. fxe8=Q+ Kg7 (only)
5. Qxe5+
Black deprived of most of his material, and if it wasn’t for a soon mate, white should also have an easy win with 6.Bxb2.
This looked almost too simple…
I found
1. Re8+ Rxe8
2. Rxe8+ Rxe8
3. f7+ Ne5 (or 3 … Re5 4. f8>Q#)
4. Bxe5+ Rxe5
5. f8>Q#
Not sure if I’m missing anything, but I’m sure Rd5 RxR would not work since f7 would not be a checkmate, Rxd4 would solve the problem. Then white would be queen vs R+2N which is quite bad.
San
Re8 better
Hi Susan Polgar,
Well,Very simple puzzle.
White wins the game in ease.
Example
=======
1.Re8+ R*Re8
2.R*Re8 R*Re8
3.f7+ Re5
4.f8(Q)++ Mate
White wins the game in ease.
By
Venky [ India – Chennai ]
1. Re8+ Rxe8 2.f7#
As usual, I had overlooked something.
After
1. Re8+ Rxe8
2. Rxe8+ Rxe8
3. f7+ Ne5
of course the most efficient continuation is:
4. Bxe5+ Rxe5
5. f8=Q#
Still, my solution was at least better than the pitfall:
1. Re8+ Re8
2. f7#
f7 played too soon!
It’s necessary to trade off both rooks here first!