White to move. How should White proceed?
3r1q1k/p3R1rp/1bp3p1/1pn2bP1/3Q2p1/PB6/KP5P/4R1B1 w – – 0 1
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White to move. How should White proceed?
3r1q1k/p3R1rp/1bp3p1/1pn2bP1/3Q2p1/PB6/KP5P/4R1B1 w – – 0 1
1. Qxg7+ Qxg7
2. Re8+ Rxe8
3. Rxe8+ Qg8
4. Bd4#
And 2. … Qg8 is just met with 3. Rxg8 Rxg8, 4 Bd4#
qxg7+
damn easy…
Qxd8+ Qxd8 Re8+ Qxe8 Rxe8 Rg8 Bd4#
1 Qxg7+ Qxg7
2 Re8+ Qf8
3 Bd4+ Rxd4
4 Rxf8+ Kg7
5 Rg8# does it.
A forcing way to play is, 1. Qxg7 Qxg7+ 2. Re8+:
2….Rxe8 3. Rxe8+ Qf8 4. Rxf8+ Kg7 5. Rg8#
2. …Qf8 3. Bd4+ Rxd4 4. Rxf8+ Kg7 5. Rg8#
2. …Qg8 3. Rxg8+ Rxg8 4. Bd4+ Rg7 5. Re8#.
1. Q:g7+ Q:g7 2. Re8+ R:e8 3. R:e8+ Qg8 4. Bd4# or R:g8#
Also possible is 2…Qg8 3. R:g8+ R:g8 4. Bd4+ Rg7 5. Re8#
Sac the Q and put the B on her square.
1. QxR+ QxQ
2. RxQ (a) KxR
3. Re7+ Kh8
4. Bd4#
2. … (b) any move other than KxR
3. Rg8+ RxR
4. Bd4+ Rg7
5. Re8#
Mark
I think the following is forced:
Re8 Rxe8
Rxe8 Qxe8
Qxg7+ Kxg7
Bd4+ Qe5
Bxd4#
Tim Loves Tiffanie
Pardon me, on the main line I missed the point that the black R on d8 can capture the B on d4. Doesn’t change the outcome.
1. QxR+ QxQ
2. RxR+ KxR
3. Re7+ Kh8
4. Bd4+ RxB
5. Re8+ Kg7
6. Rg8#
Mark
Qxd8 Qxd8
Re8+ Rg8
Bd4 Qxd4
Rxg8++
Qxd8 Qxd8
Re8+ Qxe8
Rxe8 Rg8
Rxg8++
1.Qxd8 Bxd8 2.Re8 Rg8 3.Bd4+ wins
This one is easy, but only once you see it: It is a mate in 5—with a third move Bd4+ which is unusual (removing the R as the back rank protector). And again it utilizes pawns blocking escape holes for the mate. (However, I considered first a very neat, quieter move 1. Qc3 ostensibly unleashing the B on g1 onto the d4–h8 diagonal. But it fails dismally to 1.…N*b3. And so this is just another utilization of that B.)
Psyche/ anonymous
1. Qg7+! Q*g7
2. Re8+ Qf8
3. Bd4+! R*d4
4. R*f8 Kg7
5. Rg8#
1. Qxg7+, Qxg7
2. Re8+, Rxe8 (Qf8 leads to RxQ, RxR, Bd4 and mate next)
3. Rxe8+ and mate next move.
1.Qxg7+ Qxg7
2.Re8+ Qg8
3.Rxg8+ Kxg8
4.Re8+ Kg7
5.Rg8#
– From MR KO (Malaysian)
This seems to be a mate in 5 with the best defense from black. And guess what, it is the white’s bishop pair that strangles the black king in that dark corner.
1.Qxg7+ Qxg7
2.Re8+
Black has 3 options here. First one
2…Rxe8
3.Rxe8+ Qg8 (3…Qf8)
4.Bd4#
Second one
2…Qg8
3.Rxg8+ Rxg8
4.Bd4#
Third one
2…Qf8
3.Rxf8+ Rxf8
4.Bd4+ Rf6
5.Bxf6#
White mates in 5 moves after a queen sacrifice.
1. Qxg7+, Qxg7 (the only move)
2. Re8+, Qf8 (2..,Rxe8; 3.Rxe8+, and white wins on the next move with either 4. Rxg8#, or 4. Bd4#)
3. Bd4+!, Rxd4
4. Rxf8+, Kg7
5. Rg8 checkmate.
Erik Fokke
Amsterdam, Netherlands
Qxg7+ Qxg7
Re8+ Qf8
Bd4+ Rxd4+
Rxf8+ Kg7
Rf7+ Kh8
Re8++
I completly ignored the bishop in the first solution.. This is a better solution
i think. this is the right way to start the massacre:
1. Qxg7+ Qxg7
2. Re8+ Qf8/g8
3. Bd4+ Rxd4
4. Rxf8/g8#
2. … Rxe8
3. Rxe8+ Qf8/g8
4. Rxf8/g8 or Bd4#
greets, jan
This looks like easy mate in 4 to me:
1. Qxg7 Qxg7 (freeing d4 for bishop was important here)
2. Re8+ Rxe8 (giving queen fails to Bd4#)
3. Rxe8+ Qg8/f8
4. Bd4#
1.Qxg7+ Qxg7 2.Re8+ Qf8 the best try 3.Bd4+ Rxd4 4.Rxf8+ Kg7 5.Rg8 mate !
Bad: Qxd8 Bxd8
Re8 looks better
I see this line the best:
Qxg7+ Qxg7
Re8+ Rxe8
Rxe8+ Qg8
Bd4++
The first four comments are all inaccurate. This is a forced mate:
1. Qxg7+ Qxg7
2. Re8+ Qf8
(if 2. … Rxe8, 3. Rxe8+ Qg8, 4. Rxg8 mate)
(if 2. … Qg8, 3. Bd4+ Rxd4, 4. Rxg8 mate)
3. Bd4+ Rxd4
4. Rxf8+ Kg7
5. Rf7+ Kg8
6. Re8 mate
In the 1 Re8 line, Bd4+ doesn’t mate. Black can play Kf8.
Also 1 Qxd8 doesn’t work:
1 Qxd8 Bxd8
2 Re8 Nd7!
3 Rf8+ Nf8
4 Re8 Be7
5 Bd4 Bd6
5 Be5+! Bc5
Of course, Black can’t take the Bishop
6 Bd4!
After Bxg7+ Kxg7, Black has two pieces and two pawns for the Rook and should win.
With the given move, White’s Bishop follows Black’s Bishop back and forth for a draw by repetition.
White, who is down a piecd and two pawns, does have a winning line, though.
1 Qxg7+!
White needs to operate with check. On 1 Rxg7 Nxb3, Black removes one of the annoying Bishops, and White no longer has a mating net.
1…. Qxg7
2 Re8+ Qf8
Black’s other two choices are no better: 2 … Qg8 is met by 3 Bd4+ Rxd4, 4 Qxg8#, and 2 … Rxe8 falls to 3 Rxe8+ Qany, 4 Bd4#
3 Bd4+ Rxd4
4 Rf8+ Kg7
5 Rg8#