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      Home  >  Chess Improvement • Chess Puzzles  >  Tricky stuff

      Tricky stuff

      Chess tactic, Puzzle Solving


      White to move. How should White proceed?

      7n/3P4/p6R/1k4p1/2pK4/8/6r1/8 w – – 0 1

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      21 Comments

      1. AlbuquerqueWJr Reply
        February 1, 2010 at 6:03 am

        1.Rb6! Ka5 (if 1…Kxb6 2.d8=(Q)+) 2.Rb2! Rxb2 3.d8=(Q)+ and 4.Qxh8

      2. Anonymous Reply
        February 1, 2010 at 6:03 am

        1.Rb6 Ka5 2.Rb2+-

      3. Anonymous Reply
        February 1, 2010 at 6:18 am

        Rb6

      4. Anonymous Reply
        February 1, 2010 at 6:24 am

        This is way too tricky. Can you give a hint?

      5. Dan Scoones Reply
        February 1, 2010 at 6:57 am

        White has to start with 1.Rb6+! If Black takes, then White queens with check, gives a couple of other checks, and picks up the rook (which is stronger than taking the knight). Black can’t allow this, so he has to play 1…Ka5. Now Black is threatening to stop White from queening, with either 2…Nf7 or 2…Rd2. White’s defence to this idea: 2.Rb2! Now 2…Nf7 3.Rxg2 is obviously hopeless, but so too is 2…Rxb2 3.d8Q+ followed by 4.Qxh8. A nice sequence based on attraction, line-clearing, and deflection.

      6. Anonymous Reply
        February 1, 2010 at 7:28 am

        Kc3 is best move to handle the game. other moves are listed as follows.

        Kc3-Nf7
        Rh7-Rf2
        R*f7-R*f7
        d8(promote to Queen)

        Mahyar Esteki
        (Manager of Independent Chess Players of APIIT University – ICPA)

      7. john Reply
        February 1, 2010 at 7:38 am

        1. Rb7 ..Kxb7
        2. d8Q ..Kb5
        3. Qd5 .. rook falls

      8. Anonymous Reply
        February 1, 2010 at 7:52 am

        Rh2 maybe?

      9. William Reply
        February 1, 2010 at 8:02 am

        It’s beyond me. I’m thinking Kd5 or Ke5 is the key, but even they seem to leave me with inferior endgames.

      10. Anonymous Reply
        February 1, 2010 at 8:32 am

        1. Rb6+
        if 1..Kxb6 then 2.Pd8(Q)+ wins
        if 1..Ka6 then 2.Rb2 wins (2..Rxb2, Pd8(Q)+, then 3..Qxh8)
        if 1..Ka5 then Pd8(Q) wins ( Rd2+, 2. Kxc4 2..Rxd8, Rxa6#)

        it was surprisingly tricky to see the check by promotion.

      11. aam2010 Reply
        February 1, 2010 at 8:53 am

        1. Rb6+ Ka4
        2. d8(Q) Rd2+
        3 Kxc4
        threatening Rxa6# so black cannot take the Q

        or
        1. Rb6+ Kxb6
        2. d8(Q)+
        and 3. Qxh8

        or
        1. Rb6+ Ka5
        2. Rb2 Rxb2
        3. d8(Q)+
        and 4. Qxh8

      12. Anonymous Reply
        February 1, 2010 at 9:57 am

        1. Rh6-b6+

        A. If 1. … Kb5xb6 2. d7-d8Q+ queens with tempo.

        B. If 1. … Kb5-a5
        2. Kd4-c5 Rg2-d2 (not forced)
        3. Rb6-d6 Rd2xd6
        4. Kc5xd6 Nh8-f2+
        5. Kd6-e7 Nf2-d8
        6. Ke7xd8 c4-c3
        7. Kd8-e7 c3-c2
        8. d7-d8Q+ queens with tempo then cleans up the pawn on g5 and then the pawn on c1 if it queens next move.

        C. If 1. … Kb5-a4
        If now 2. Kd4-c5 … this time the pawn may not queen with tempo, and it would be difficult to clean up black’s pawns.
        White instead has to try and clean up black’s pawns right away, starting with 2. Rb6xa6+

        –br

      13. Anonymous Reply
        February 1, 2010 at 11:07 am

        1.Rb6+ Kxb6
        2.d8=Q+

        if 1…Ka5
        2.Rb2 Rxb2
        3.d8=Q+

        if 1…Ka4
        2.d8=Q Rd2+
        3.Kxc4 Rxd8
        4.Rxa6++
        or 3…Rc2+
        4.Kd3

      14. Anonymous Reply
        February 1, 2010 at 12:09 pm

        hmm Rb6+ looks ok…

      15. Anonymous Reply
        February 1, 2010 at 12:10 pm

        Rb6+ looks good to me

      16. Anonymous Reply
        February 1, 2010 at 12:11 pm

        Hi!

        I didn’t concretely see the solution but I saw some ideas.

        1Rb6+Ka5 2Kc5Nf7(Rd2? 3Rb2!)3Rb1Ka4 4Rf1(Kxc4? Ne5+)Nd8 5Kxc4

        if 5..Rc2+ 6Kd5 6..Nb7 7Rb1
        6..g4 7Kd6! and then Rf8 and Rb8

        if 5..Ka5 6Kc5 Rc2+ 7Kd5 Nf7 8Rf1 Rd2+ 9Kc4 Rc2+ 10Kd5 Nd8 11Kd6! and then Rf8 and Rb8

      17. Anonymous Reply
        February 1, 2010 at 12:14 pm

        Rh2

      18. Anonymous Reply
        February 1, 2010 at 12:15 pm

        Rb6+

      19. Asbjørn Reply
        February 1, 2010 at 1:22 pm

        1 Rb6+ Ka5
        (1 .. Kxb6 2 d8=Q+ and the rook will fall after a check in the h1-a8 diagonal)
        (1 .. Ka4 2 d8=Q Rd2+ 3 Kxc4 Rxd8 4 Rxa6#)
        2 Rb2 Rxb2
        3 d8=Q+ Ka4
        … and the lack of coordination between black’s pieces gives White a winning advantage.

      20. Timothée Tournier Reply
        February 1, 2010 at 5:52 pm

        1.Rb6! Ka5 (Ka4 2. Kxc4!) 2.Rb2!!

      21. Cortex Reply
        March 16, 2011 at 11:54 pm

        Very tricky endgame indeed.

        1 Rb6+ Ka5
        2 Rb2 Rxb2
        3 d8=Q+ Ka4
        and the solution intended by the composer was
        4.Kxc4, which must win

        (Prokes, Casino di Saragossa, 1929, #10, third prize)

      Leave a Reply to AlbuquerqueWJr Cancel reply

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