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      Home  >  Chess Improvement • Chess Puzzles  >  World Cup brilliancy

      World Cup brilliancy

      Chess tactic, Puzzle Solving


      White to move. How should White proceed?

      Source: ChessToday.net

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      14 Comments

      1. Anonymous Reply
        November 29, 2009 at 4:53 am

        1.Rc2, Rxc2
        2.Rxc2, Rxc2
        3.b7, Rb2
        4.Nd7+, Ke8
        5.Nb6, …
        6.b8:Q

      2. yves Reply
        November 29, 2009 at 5:37 am

        1. R5c2 (to prevent black’s Rxg2)

        after rooks exchange white remains with a rook down, but Nd7+ and b7 leave the black with only one possibility to stop the b-pawn from queening: Rb2. White then is blocking the b-file by Nb6.

      3. Anonymous Reply
        November 29, 2009 at 6:10 am

        Rc5-c2

      4. aam Reply
        November 29, 2009 at 6:28 am

        1. R(c1)-c2 R(d2)xc2
        2. Rxc2

        now, if 2… Rxc2
        3. b7 Rb2
        4. a6 wins

        if 2… Rxa5
        3. Rb2 wins
        e.g., 3… Ra8, 4. b7 Rb8 5. Nd7+

        Is it really this simple?

      5. Danton Serpa Reply
        November 29, 2009 at 7:20 am

        this is not fair to me because i watched the game, but it is really brilliant! congrats karja!

      6. wolverine Reply
        November 29, 2009 at 8:32 am

        Rc2

      7. Anonymous Reply
        November 29, 2009 at 9:18 am

        R1c2

      8. Anonymous Reply
        November 29, 2009 at 9:59 am

        1.R5c2 Rdxc2 2.Rxc2 Rxc2 3.a6 followed by advancing and queening one of the a or b pawns.

      9. אייבי ויילר Reply
        November 29, 2009 at 10:05 am

        This is a good example if you want to teach students about how hard it is for a Rook to stop a pair of connected passed pawns on the 5th and the 6th rank.

        In the position, White has a clear advantage. However Black has an immediate threat of at least a draw by perpetual check. So White’s first move, if he is going for the win, has to take care of this threat.
        1. Rc1- c2. This is my main candidate move. It is actually a Rook sacrifice.
        If Black takes the Rook by 1..Rd2xc2 than follows
        2. Rc5xc2.
        If Black takes again on c2 by playing 2… Ra2xc2 than White replies forcefully with:
        3. b7 Rb2 only move.
        4. a6 followed by a7 and Black cannot stop one of these pawns from queening.

        If however Black declines to capture the poisoned Rook and plays: 2..Ra2xa5 than again White responds forcefully with
        3. b7 Rb5 only logical continuation to stop the coming promotion.
        4. b8=Q + White promotes anyway, taking advatage of the position of the Black monarch.
        4….RxQ
        5. Nd7+ A fork! Ke8
        6. NxR and next falls the c6 pawn, since the d7 square is restricted to the poor monarch to occupy and defend. A chess player in Karjakin’s measure will win such a position blindfolded.
        Nice puzzle. It took me time to solve it. Although the first move I found intuitively and fast. I did not see the continuation only after I set the pieces on a board.
        Thanks for the great blog!
        A Weiler

      10. Anonymous Reply
        November 29, 2009 at 10:19 am

        I found the idea pretty easily. It’s were logical of course given that black could force perpetual if something else was played.

        1.R5c2 Rxc2 2.Rxc2 Rxc2 3.a6 completly winning.

      11. Anonymous Reply
        November 29, 2009 at 11:26 am

        Rc2. Sac a rook and play a6, the passed pawns are unstoppable it appears.
        Regards,
        Roy

      12. Anonymous Reply
        November 29, 2009 at 11:54 am

        1.R5c2! Rc2 2.Rc2 Rc2 3.b7 Rb2 4.a6 +-

      13. . Reply
        November 29, 2009 at 12:18 pm

        Rc5c2 rxr
        rxr rxr
        b7 Rb2
        b8=Q RxB8
        Nd7+ King moves
        Knight takes queen / any
        a6…

        This doesnt seem to work I wonder what else there is

      14. Frederick Reply
        November 29, 2009 at 12:25 pm

        1.R5c2! Rdxc2 2.Rxc2 Rxc2 (2…Rxa5 3.b7 Rb5 4.b8(Q)+ Rxb8 5.Nd7+) 3.b7 (3.a6 also works) Rb2 4.a6 and Black is helpless against 5.a7

      Leave a Reply to Frederick Cancel reply

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