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      Home  >  Chess Improvement • Chess Puzzles  >  San Cristobal chess tactic

      San Cristobal chess tactic

      Chess tactic, Puzzle Solving

      Black to move. How should black proceed?

      Source: ChessToday.net

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      12 Comments

      1. Vivian Reply
        October 2, 2012 at 3:14 am

        Why not just 1. … e3, overloading the Q?

      2. lakers4sho Reply
        October 2, 2012 at 3:38 am

        e3

      3. Satya Reply
        October 2, 2012 at 4:48 am

        Black should win with
        1…..e3

        All logical continuations for White loses

        2. Qxe3 Bxb2
        or
        2. fxe3 Bxb2 3. Qxb2 Qxg3
        or
        2. Qe2 exf2+

      4. Ravi Reply
        October 2, 2012 at 7:39 am

        1…e3 2.fxe3
        (2.Qxe3 Bxb2)
        (2.Qe2 exf2+ 3.Qxf2
        (3.Kxf2 Bxb2 4.Qxb2 Qf4+ 5.Kg1 Qxg3)
        3…Bxb2 4.Qxb2 Qxg3)
        2…Qxg3 3.Bxg7 Kxg7 4.Rc2

      5. pht Reply
        October 2, 2012 at 8:22 am

        White has waited too long to trade off his dark-squared bishop. Now Bb2 is weak due to weaknesses of the Q fields c2/d2/e2.

        I didn’t see this immediately, but I saw the strong looking:

        1. e3!

        If white takes with pawn he looses knight, if he takes with queen he looses bishop.

        1. … Qc2

        Enforced because of Qe2? Bb5! and Q must leave protection of bishop.
        Here I spent some time thinking, before finding there is an actual enforcement of allready mentioned idea:

        2. Bd7! Qe2
        3. Bb5! Qxe3 (no more room for Q in 2nd rank)
        4. Bxb2
        is nicely up with bishop.

      6. Antoine Richard Reply
        October 2, 2012 at 12:19 pm

        e4-e3

      7. Anonymous Reply
        October 2, 2012 at 12:21 pm

        1. … e3
        2. Qc2 Bd7
        3. Qb3 exf2+
        4. Kxf2 Qf4+
        5. Qf3 Qxf3+
        6. Kxf3 Bxb2
        black wins a piece.
        5. Kany Bxb2
        6. Qxb2 Qxg3
        black also wins a piece.
        4. other Bxb2
        5. Qxb2 Qxg3
        black also wins a piece.
        3. Qe2/d3 Bb5
        4. Qxe3 Bxb2
        black also wins a piece.
        3. Qb1 exf2+
        4. Kxf2 Qf4+ (4. other, Qxg3)
        5. Kany Qxg3
        black wins a piece.
        3. Qd1 Bxb2
        4. Qxd7 Rxc1+ (4. Rxc8+, Qxc8)
        black wins a piece again.
        2. Qe2 Bb5
        3. Rxc8+ Qxc8
        4. Qxe3 Bxb2
        2. Qxe3 Bxb2
        2. fxe3 Qxg3
        black wins a piece in all lines.
        that was fun. greets, jan

      8. gabriele Reply
        October 2, 2012 at 5:37 pm

        1…e3-+

      9. Vishnu Vardhan Reddy. G Reply
        October 2, 2012 at 5:41 pm

        1…e3 2.QE2 (If Qxp, BxB Losses. If pxp, QxN Losses for white) 2…Bb5 (Now White must loose the Bishop on b2)-+

      10. Craig Johannsen Reply
        October 2, 2012 at 9:05 pm

        Looking at the line proposed by Vishnu, it looks better for white than for black. 3. Qg4 turns things around for white:
        1… e3
        2. Qe2 Bb5
        3. Qg4 {Things start to look bad for black now.}

        Then, if
        3… Bxb2
        4. Rxc8+ {Black now is doomed.}

        One way it could play out is:
        4… Kg7
        5. Rxb8 Bd7
        6. Qxd7 e2
        7. Nxe2 Be5
        8. Rb7 Kh6
        9. Qxf7 Bd6
        10. Rxb6 Bh2+
        11. Kxh2 a5
        12. Qf4+ Kg7
        13. Rb7+ Kg8
        14. Qf7+ Kh8
        15. Rb8# {White checkmates black!}

        Alternatively,
        4… Qxc8
        5. Qxc8+ Kg7
        6. fxe3 {The end is nigh for Black!}

        4… Be8 {Only introduces a slight delay.}
        5. Rxb8 Kf8
        6. Qe4 exf2+
        7. Kxf2 Bd4+
        8. Kf3 Be5
        9. Qxe5 f6
        10. Qxf6+ Kg8
        11. Rxe8#

        But, if, instead, 3… Rc7 or Rxc1, then black has a slight advantage.

      11. Anonymous Reply
        October 3, 2012 at 8:35 am

        Hello Craig, what if f. e. after
        1. … e3
        2. Qe2 Bb5
        3. Qg4: f5
        4. Nxf5 Rxc1+
        4. Bxc1 exf2+
        5. Kxf2 gxf5
        6. Qxf5 Bd4+?
        Okay, it looks very complicated, it just seems to me that black must be winning.
        greets, jan

      12. Craig Johannsen Reply
        October 3, 2012 at 11:24 pm

        Jan, I would agree that 2… f5 followed eventually by … Rxc1+ is a good combination for black. It is an example of the 3… Rxc1 variant that I mentioned above gives black a slight advantage. I think in this case it is more than slight, so you are correct.
        1… e3
        2. Qe2 Bb5
        3. Qg4 f5
        4. Nxf5 Rxc1+ {Black has an advantage.}
        5. Bxc1 exf2+
        6. Kxf2 gxf5
        7. Qxf5 Bd4+? {Looking even better for black.}

        This line could play out as follows:
        8. Be3 Bxe3+
        9. Kxe3 Qg3+
        10. Qf3 Qe1+
        11. Kf4 Qxb4+
        12. Kg3 {Black has a decisive advantage.}

        But, suppose that, instead of 4. Nxf5, white plays Qd1. This could play out something like:
        4. Qd1 exf2+
        5. Kxf2 Qf4+
        6. Kg1 Rxc1
        7. Qxc1 Bd4+
        8. Kh2 Qxc1 {Not good for white if this rook and queen exchange takes place this early.}
        9. Bxc1 Be5
        10. Bd2 Bd3
        11. Be1 b5
        12. Kg1 Bc4
        13. a3 Bd4+
        14. Bf2 Bb2
        15. Be1 Kf7
        16. Bd2 Bxa3 {White clearly in trouble}

        What if, instead of 4. Nxf5, white takes the initiative and captures black’s rook:
        4. Rxc8+ Qxc8
        5. Qf4 Bxb2
        6. Qxe3 Qc1+ {Black invites queen exchange.}
        7. Qxc1 Bxc1 {White obliges but now cannot defend its queen side pawns.}
        8. Nf1 Ba3
        9. Ne3 Bxb4 {Looks definitively bad for black.}

        White can even things out a little better by playing:
        4. Rxc8+ Qxc8
        5. Qd1 Bxb2
        6. Qb3+ Qc4 {Black invites queen exchange.}
        7. Qxb2 f4
        8. Ne2 Qxe2 {Black poses a mate threat, so white must exchange queens.}
        9. Qxe2 Bxe2 {White is doomed once again.}

        If, white declines to exchange queens in the preceding line of play, then black will play Qxf2+ and the end comes rather quickly. For example:
        9. Qd4 Qxf2+
        10. Kh1 Bf1
        11. Qxe3 Qxg2#

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